My interpretation is that terms normal or parallel to ridge pertain to the wind direction, not the surfaces. If pressed for an answer, I believe I'd characterize the green surface as normal to the ridge, but I believe that's not how one enters Figure 27.3-1. For your image the wind is parallel to the ridge, and if it were 90 degrees from what you show, it would be normal to the ridge.
However, by this interpretation it appears that Fig 27.3-1 does not explicitly consider all faces of a hip roof. which might be the crux of your question. In particular, when wind is parallel to the ridge, one enters the second table you show and does not find a value for a windward roof surface (i.e., your green surface). Hmmm, not sure there. I’d suppose the programmers for the software you use also wrestled with this and decided to go back to the first table you show, even though wind is not normal to the ridge as the heading indicates.
This means that for the green face you’d use the value(s) for the windward face in the first table at whatever angle and h/L you have, even though the wind is actually parallel to the ridge (i.e., contrary to the heading of normal). This also applies to the leeward face, which is hidden in your figure. For the sides of the roof (pink, gray, and brownish) you’d return to the second table because the wind is indeed (still) parallel to the ridge. I believe that’s what I’d do.
Hope this helps,